Amperage is
the Current, Volts is the potential, and Watts (in simple terms) is Current x
Voltage.
Therefore the
wattage formula is: Watts = Current X Voltage
And Resistance
(Ohm) = Voltage / Current
The Resistance
(R) of a material depends on its length, cross-sectional area, and the
resistivity
(the Greek letter rho), a number that depends on the material:
The
resistivity and conductivity are inversely related. Good conductors have low
resistivity, while
poor conductors (insulators) have resistivities that can be 20 orders of
magnitude larger.
When we
compare two ionizers, setting both machines at same level of current output at
5 amperage,
ionizer ONE that provides 1 Resistance and ionizer TWO provides 2 resistance
from the conductors:
Plug into the formula above, we will find that the Voltage produce by both
ionizers are as following:
ONE = 5V , and TWO = 10V.
Then we now
plug both ionizers’ voltage values in the wattage formula, we will get: ONE =
25Watts,
and TWO = 50Watts.
Ionizer ONE: 1
(R) = 5V / 5 amperage
Ionizer TWO: 2
(R) = 10V / 5 amperage
Then, plug
into the wattage formula:
Ionizer ONE:
25 watts = 5 amperage X 5V
Ionizer TWO:
50 watts = 5 amperage X 10V
Finally, Ionizer TWO needs larger Wattage to produce
the same quality output as ionizer ONE at the
same level of current/amperage. This is caused by poorer plate conductivity in
ionizer TWO. On the
other hand, ionizer ONE with lower wattage needed has more efficient plate
conductivity. In today’s
electronics, low wattage not only an indicator of good conductivity, but also
save power and prevent
electronics from heating up and aging quickly.
